Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 69

Answer

$x,(x-2),(x-13)$

Work Step by Step

Given:$x^3-15x^2+26x$ Take the common terms out. Thus, $=x(x^2-15x+26)$ or, $=x(x^2-13x-2x+26)$ or, $=x[x(x-13)-2(x-13)]$ or, $=x(x-2)(x-13)$ Hence, Factors are :$x,(x-2),(x-13)$
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