Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 61



Work Step by Step

Given:$x^2+18x+8-y^2$ Since, $a^2-2ab+b^2=(a-b)^2$ Thus, $=(x)^2-2(9)(1x)+(9)^2-y^2$ or, $=(x+9)^2-y^2$ Since, $a^2-b^2=(a-b)(a+b)$ Hence, $(x-y+9)(x+y+9)$
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