Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 63



Work Step by Step

Given:$64x^3+27$ Since, $a^3+b^3=(a+b)(a^2-ab+b^2)$ Thus, $=(4x)^3-(3)^3$ or, $=(4x+3)(16x^2-(4x)(3)+9$ Hence, $(4x+3)(16x^2-12x+9)$
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