Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 70


Three Factors are :$-2y^2(y-3)(y-9)$

Work Step by Step

Given:$-2y^4+24y^3-54y^2$ Take the common terms out. Thus, $=-2y^2(y^2-12y+27)$ or, $=-2y^2(y^2-9y-3y+27)$ or, $=-2y^2(y-3)(y-9)$ Hence, Three Factors are :$-2y^2(y-3)(y-9)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.