## Intermediate Algebra for College Students (7th Edition)

Three Factors are :$-2y^2(y-3)(y-9)$
Given:$-2y^4+24y^3-54y^2$ Take the common terms out. Thus, $=-2y^2(y^2-12y+27)$ or, $=-2y^2(y^2-9y-3y+27)$ or, $=-2y^2(y-3)(y-9)$ Hence, Three Factors are :$-2y^2(y-3)(y-9)$