Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 53



Work Step by Step

Given:$1-81x^2y^2$ Equation can be written as: $=(1)^2-(9xy)^2$ Since, $a^2-b^2=(a-b)(a+b)$ Hence, $(1-9xy)(1+9xy)$
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