Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 89



Work Step by Step

Given: $a^8-1$ This implies that $=(a^4)^2-1^2$ or, $=(a^4-1)(a^4+1)$ or,$=(a^2-1)(a^2+1)(a^4+1)$ Hence, our Factors are: $(a-1),(a+1),(a^2+1),(a^4+1)$
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