Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 62



Work Step by Step

Given:$z^2-25x^2+10x-1$ Since, $a^2-2ab+b^2=(a-b)^2$ Thus, $=z^2-[(5x)^2-2(5)(x)+(1)^2]$ or, $=z^2-(5x-1)^2$ Since, $a^2-b^2=(a-b)(a+b)$ Hence, $(z-5x+1)(z+5x-1)$
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