Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 81



Work Step by Step

Given: $4a^3+32$ This implies that $=4(a^3+8)$ or, $=4(a^3+2^3)$ or, $=4(a+2)(a^2+4-2a)$ Hence, our Factors are: $4,(a+2),(a^2+4-2a)$
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