Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 79


$(x^2-3)^2$ or, $(x^2-3)(x^2-3)$

Work Step by Step

Given: $x^4-6x^2+9$ or, $=(x^2)^2-6x^2+9$ This implies $=(x^2)^2-3x^2-3x^2+9$ or, $=(x^2-3)(x^2-3)$ Hence, Factors are: $(x^2-3)^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.