Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 17



Work Step by Step

Given:$(7xy^2)(3x^4y^2-5xy-1)$ Multiply the given polynomials. This implies $(7xy^2)(3x^4y^2-5xy-1)=21x^{4+1}y^{2+2}-35x^2y^3-7xy^2$ Hence, the result is : $=21x^{5}y^{4}-35x^2y^3-7xy^2$
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