Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 82



Work Step by Step

Given: $x^4-81$ This implies that $=(x^2)^2-(9)^2$ or, $=(x^2-9)(x^2+9)$ or, $=(x-3)(x+3)(x^2+9)$ Hence, our Factors are: $(x-3),(x+3),(x^2+9)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.