Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 19



Work Step by Step

Given:$(x^2+x-1)(x^2+3x+2)$ Multiply the given polynomials. This implies $=x^4+3x^3+2x^2+x^3+3x^2+2x-x^2-3x-2$ or, $=x^4+3x^3+x^3+2x^2+3x^2-x^2+2x-3x-2$ Hence, the result is : $=x^4+4x^3+4x^2-x-2$
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