Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 75



Work Step by Step

Given: $2y^3+12y^2+18y$ or, $=2y(y^2+6y+9)$ This implies $=2y(y^2+3y+3y+9)$ or, $=2y(y+3)(y+3)$ Hence, Factors are: $2y,(y+3)^2$
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