Answer
$2y,(y+3)^2$
Work Step by Step
Given: $2y^3+12y^2+18y$
or, $=2y(y^2+6y+9)$
This implies
$=2y(y^2+3y+3y+9)$
or, $=2y(y+3)(y+3)$
Hence, Factors are: $2y,(y+3)^2$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Review Exercises - Page 400: 75
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