Two factors are: $(3x-y),(2x-7y)$
Work Step by Step
Given: $6x^2-23xy+7y^2$ or, $=6x^2-21xy-2xy+7y^2$ This implies $=3x(2x-7y)-y(2x-7y)$ or, $=(3x-y)(2x-7y)$ Hence, Two factors are: $(3x-y),(2x-7y)$
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