Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 26



Work Step by Step

Given:$[(x+3)+5y][(x+3)-5y]$ Apply Formula: $(a-b)(a+b)=a^2-b^2$ This implies $[(x+3)+5y][(x+3)-5y]=(x+3)^2-(5y)^2$ or, $=x^2+9+6x-25y^2$ Hence, the result is : $x^2-25y^2+6x+9$
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