Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 42



Work Step by Step

Given:$3x^3-36x^2+33x$ Factorzie the equation then it can be written as: $=3x(x^2-12x+11)$ or, $=3x[x(x-11)-1(x-11)]$ Hence, $=3x(x-11)(x-1)$
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