Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 77



Work Step by Step

Given: $8x^3-27$ or, $=(2x)^3-(3)^3$ This implies $=(2x-3)[(2x)^2+3^2+3x+2x]$ or, $=(2x-3)(4x^2+6x+9)$ Hence, Factors are: $(2x-3),(4x^2+6x+9)$
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