Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 35



Work Step by Step

Given:$-x^2-11x+14$ Since, $GCF=-1$ Take out the $-4$ from the given equation, then the equation can be written as: $=-x^2-11x+14$ $=-1(x^2+11x-14)$ Hence, $-(x^2+11x-14)$
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