Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 34



Work Step by Step

Given:$-12x^2+8x-48$ Since, $GCF=-4$ Take out the $-4$ from the given equation, then the equation can be written as: $=-12x^2+8x-48$ Hence, $=-4(3x^2-2x+12)$
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