Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 25



Work Step by Step

Given:$(3xy^2-4x)(3xy^2+4x)$ Apply Formula: $(a-b)(a+b)=a^2-b^2$ This implies $(3xy^2-4x)(3xy^2+4x)=(3xy^2)^2-(4x)^2$ or, $=9x^2y^4-16x^2$ Hence, the result is : $9x^2y^4-16x^2$
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