Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 71


Two Factors are :$(3x-5)(3x-5)$ or, $(3x-5)^2$

Work Step by Step

Given:$9x^2-30x+25$ $=9x^2-(15x+15x)+25$ or, $=9x^2-15x-15x+25$ or, $=3x(x-5)-5(3x-5)$ Hence, Two Factors are :$(3x-5)(3x-5)$ or, $(3x-5)^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.