Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 65



Work Step by Step

Given:$x^3y^3+1$ Since, $a^3+b^3=(a+b)(a^2-ab+b^2)$ Thus, $=(xy)^3+(1)^3$ or, $=(xy+1)(x^2y^2-xy+1)$ Hence, $(xy+1)(x^2y^2-xy+1)$
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