Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 400: 60



Work Step by Step

Given:$25x^2-40xy+16y^2$ Thus, $25x^2-40xy+16y^2=(5x)^2-2(5x)(4y)+(4y)^2$ Since, $a^2-2ab+b^2=(a-b)^2$ Here, $a=5x, b=4y$ Hence, $(5x-4y)^2$
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