Answer
$\dfrac{1}{(x+1)^2}$
Work Step by Step
Simplify $\dfrac{d(\dfrac{x}{x+1}+C)}{dx}$
Thus, we have
$\dfrac{d(\dfrac{x}{x+1}+C)}{dx}=\dfrac{d(1-\dfrac{1}{x+1}+C)}{dx}=(x+1)^{-2}=\dfrac{1}{(x+1)^2}$
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