Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 70

$\tan \theta +C$

Given: $\int \dfrac{\csc \theta}{(\cos \theta \cot \theta)}$ Thus, $\int \dfrac{\csc \theta}{(\cos \theta \cot \theta)}=\int \dfrac{1/\sin \theta}{\cos \theta (\dfrac{\cos \theta}{\sin \theta})} =\int sec^2 \theta=\tan \theta +C$