University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 53


$- e^{-x}+\dfrac{4^x}{\ln 4} +C$

Work Step by Step

Given: $\int (e^{-x} +4^x) dx$ Thus, $\int (e^{-x} +4^x) dx=(-1) e^{-x}+\dfrac{4^x}{\ln 4} +C=- e^{-x}+\dfrac{4^x}{\ln 4} +C$
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