University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 72

Answer

$(3x+5)^{-2}$

Work Step by Step

Simplify: $\dfrac{d(-\dfrac{(3x+5)^{-1}}{3}+C)}{dx}$ Thus, we have $\dfrac{d(-\dfrac{(3x+5)^{-1}}{3}+C)}{dx}=(3)[\dfrac{(3x+5)^{-2}}{3}]=(3x+5)^{-2}$
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