University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 25


See below.

Work Step by Step

Since, we have $\int (x+1) dx=\dfrac{x^2}{2}+x+C$ and $\dfrac{d}{dx}(\dfrac{x^2}{2}+x+C)=x+1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.