Answer
$\dfrac{y}{7}+\dfrac{4}{y^{1/4}} +C$
Work Step by Step
Given: $\int (\dfrac{1}{7}-\dfrac{1}{y^{5/4}})dy$
Since, we have $\int x^n dx=\dfrac{x^{n+1}}{n+1}+C$
Thus, $\int (\dfrac{1}{7}-\dfrac{1}{y^{5/4}})dy=\dfrac{y}{7}-(-\dfrac{y^{-5/4+1}}{-5/4+1}) +C=\dfrac{y}{7}+\dfrac{4}{y^{1/4}} +C$
