University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 38


$\dfrac{y}{7}+\dfrac{4}{y^{1/4}} +C$

Work Step by Step

Given: $\int (\dfrac{1}{7}-\dfrac{1}{y^{5/4}})dy$ Since, we have $\int x^n dx=\dfrac{x^{n+1}}{n+1}+C$ Thus, $\int (\dfrac{1}{7}-\dfrac{1}{y^{5/4}})dy=\dfrac{y}{7}-(-\dfrac{y^{-5/4+1}}{-5/4+1}) +C=\dfrac{y}{7}+\dfrac{4}{y^{1/4}} +C$
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