University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 43

Answer

$-2 \sin t +C$

Work Step by Step

Given: $\int (-2 \cos t) dt$ Thus, $\int (-2 \cos t) dt=-2 \sin t +C$ and $\dfrac{d}{dt}(-2 \sin t +C)=-2 \cos t$
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