University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 37


$4y^2-\dfrac{8y^{3/4}}{3} +C$

Work Step by Step

Given: $\int (8y-\dfrac{2}{y^{1/4}})dy$ We have: $\int x^n dx=\dfrac{x^{n+1}}{n+1}+C$ Thus, $\int (8y-\dfrac{2}{y^{1/4}})dy=4y^2-\dfrac{2y^{3/4}}{3/4} +C=4y^2-\dfrac{8y^{3/4}}{3} +C$
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