Answer
$4y^2-\dfrac{8y^{3/4}}{3} +C$
Work Step by Step
Given: $\int (8y-\dfrac{2}{y^{1/4}})dy$
We have: $\int x^n dx=\dfrac{x^{n+1}}{n+1}+C$
Thus, $\int (8y-\dfrac{2}{y^{1/4}})dy=4y^2-\dfrac{2y^{3/4}}{3/4} +C=4y^2-\dfrac{8y^{3/4}}{3} +C$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 37
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