University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 45


$-21 \cos (\dfrac{\theta}{3})+C$

Work Step by Step

Given: $\int 7 \sin (\dfrac{\theta}{3}) d\theta$ Thus, $\int 7 \sin (\dfrac{\theta}{3}) d\theta=7(-3) \cos (\dfrac{\theta}{3}) +C=-21 \cos (\dfrac{\theta}{3})+C$ and $\dfrac{d}{d \theta}(-21 \cos (\dfrac{\theta}{3})+C)=21 \sin (\dfrac{\theta}{3})(\dfrac{1}{3}=7 \sin (\dfrac{\theta}{3})$
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