Answer
$\dfrac{x}{5}+\dfrac{1}{x^2}+x^2+C$
Work Step by Step
We have: $\int (\dfrac{1}{5}-\dfrac{2}{x^3}+2x) dx=\dfrac{x}{5}+\dfrac{1}{x^2}+x^2+C$
and
$\dfrac{d}{dx}(\dfrac{x}{5}+\dfrac{1}{x^2}+x^2+C)=\dfrac{1}{5}-\dfrac{2}{x^3}+2x$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 32
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