University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 32



Work Step by Step

We have: $\int (\dfrac{1}{5}-\dfrac{2}{x^3}+2x) dx=\dfrac{x}{5}+\dfrac{1}{x^2}+x^2+C$ and $\dfrac{d}{dx}(\dfrac{x}{5}+\dfrac{1}{x^2}+x^2+C)=\dfrac{1}{5}-\dfrac{2}{x^3}+2x$
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