Answer
$\dfrac{3}{5} \sin 5\theta +C $
Work Step by Step
Given: $\int (3 \cos 5\theta) d\theta$
Thus, $\int (3 \cos 5\theta) d\theta=\dfrac{3}{5} \sin 5\theta +C $
and
$\dfrac{d}{d \theta}(\dfrac{3}{5} \sin 5\theta +C )=3 \cos 5\theta$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 46
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