Answer
$2e^{x}+\dfrac{3}{2}e^{-2x} +C$
Work Step by Step
Given: $\int (2e^{x}-3e^{-2x}) dx$
Thus, $\int (2e^{x}-3e^{-2x}) dx=2e^{x}-(-\dfrac{3}{2})e^{-2x} +C=2e^{x}+\dfrac{3}{2}e^{-2x} +C$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 52
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