University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 52


$2e^{x}+\dfrac{3}{2}e^{-2x} +C$

Work Step by Step

Given: $\int (2e^{x}-3e^{-2x}) dx$ Thus, $\int (2e^{x}-3e^{-2x}) dx=2e^{x}-(-\dfrac{3}{2})e^{-2x} +C=2e^{x}+\dfrac{3}{2}e^{-2x} +C$
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