Answer
$-\dfrac{1}{2} \cos 2x +\cot x+C$
Work Step by Step
Given: $\int (\sin 2x ) dx - \int (\csc^2 x) dx$
Thus, $\int (\sin 2x ) dx - \int (\csc^2 x) dx=-\dfrac{1}{2} \cos 2x -(-\cot x)+C=-\dfrac{1}{2} \cos 2x +\cot x+C$
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