University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 57


$-\dfrac{1}{2} \cos 2x +\cot x+C$

Work Step by Step

Given: $\int (\sin 2x ) dx - \int (\csc^2 x) dx$ Thus, $\int (\sin 2x ) dx - \int (\csc^2 x) dx=-\dfrac{1}{2} \cos 2x -(-\cot x)+C=-\dfrac{1}{2} \cos 2x +\cot x+C$
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