Answer
$\sin 2x+\cos 3x+C$
Work Step by Step
Given: $ 2 \int (\cos 2x ) dx - 3 \int (\sin 3x) dx$
Thus, $2 \int (\cos 2x ) dx - 3 \int (\sin 3x) dx=(2)(\dfrac{1}{2}) \sin 2x -3\dfrac{1}{3}(\cot 3x)+C=\sin 2x+\cos 3x+C$
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