Answer
$\dfrac{1}{(x+1)^2}$
Work Step by Step
Simplify: $\dfrac{d((\dfrac{-1}{x+1})+C)}{dx}$
Thus, we have
$\dfrac{d((\dfrac{-1}{x+1})+C)}{dx}=(x+1)^{-2}=\dfrac{1}{(x+1)^2}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 75
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
