$\theta+\tan \theta +C$
Work Step by Step
Given: $\int 2 d\theta + \int (\tan^2 \theta )d\theta$ Thus, $\int 2 d\theta + \int (\tan^2 \theta )d\theta= 2 \theta + \int (\sec^2 \theta )d\theta -\int 1 d\theta=\theta+\tan \theta +C$
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