Answer
$x^2+2x^{-1}+C$
Work Step by Step
Given: $\int 2x(1-x^{-3}) dx$
Since, we have $\int x^n dx=\dfrac{x^{n+1}}{n+1}+C$
Thus, $\int 2x(1-x^{-3}) dx=\int (2x-2x^{-2}) dx=x^2+\dfrac{2}{x}+C=x^2+2x^{-1}+C$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 39
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