University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 39



Work Step by Step

Given: $\int 2x(1-x^{-3}) dx$ Since, we have $\int x^n dx=\dfrac{x^{n+1}}{n+1}+C$ Thus, $\int 2x(1-x^{-3}) dx=\int (2x-2x^{-2}) dx=x^2+\dfrac{2}{x}+C=x^2+2x^{-1}+C$
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