University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 51


$\dfrac{1}{3}e^{3x}-5e^{-x} +C$

Work Step by Step

Given: $\int (e^{3x}+5e^{-x}) dx$ Thus, $\int (e^{3x}+5e^{-x}) dx=\dfrac{1}{3}e^{3x}+5(-1)e^{-x}) +C=\dfrac{1}{3}e^{3x}-5e^{-x} +C$
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