Answer
$(7x-2)^3$
Work Step by Step
Simplify: $\dfrac{d(\dfrac{(7x-2)^4}{28}+C)}{dx}$
Thus, we have
$\dfrac{d(\dfrac{(7x-2)^4}{28}+C)}{dx}=(4)[\dfrac{(7x-2)^3}{28}](7)=(7x-2)^3$
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