University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 54


$\dfrac{(1.3)^x}{\ln (1.3)}+C$

Work Step by Step

Given: $\int (1.3)^x dx$ Use formula: $\int a^x dx= (\dfrac{1}{\ln a}) a^x +C$ Thus, $(1.3)^x dx=[\dfrac{1}{\ln (1.3)}] (1.3)^x +C=\dfrac{(1.3)^x}{\ln (1.3)}+C$
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