University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 49


$-\dfrac{\csc \theta}{2}+C$

Work Step by Step

Given: $\int (\dfrac{1}{2} \csc \theta \cot \theta) d\theta$ Thus, $\int (\dfrac{1}{2} \csc \theta \cot \theta) d\theta= \dfrac{1}{2}\int ( \csc \theta \cot \theta) d\theta=-\dfrac{\csc \theta}{2}+C$
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