University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 27



Work Step by Step

We have $\int (3t^2+\dfrac{t}{2}) dt=t^3+\dfrac{t^2}{4}+C$ and $\dfrac{d}{dt}(t^3+\dfrac{t^2}{4}+C)=3t^2+\dfrac{t}{2}$
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