University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 33



Work Step by Step

Since, we have $\int x^{-1/3}dx=\dfrac{3}{2}x^{\frac{2}{3}}+C$ and $\dfrac{d}{dx}(\dfrac{3}{2}x^{\frac{2}{3}}+C)=x^{-1/3}$
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