Answer
$\csc^2 (\dfrac{x-1}{3})$
Work Step by Step
Simplify: $\dfrac{d(-3 \cot(\dfrac{x-1}{3})+C)}{dx}$
Thus, we have
$\dfrac{d(-3 \cot(\dfrac{x-1}{3})+C)}{dx}=(3)[\dfrac{1}{3 \sin^2 (\dfrac{x-1}{3})}]=\csc^2 (\dfrac{x-1}{3})$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 272: 74
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