Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Section 7.1 - Trigonometric Identities - 7.1 Exercises - Page 543: 49

Answer

$\csc x\cos^{2}x+\sin x=\csc x$

Work Step by Step

$\csc x\cos^{2}x+\sin x=\csc x$ Substitute $\csc x$ with $\dfrac{1}{\sin x}$: $\Big(\dfrac{1}{\sin x}\Big)\cos^{2}x+\sin x=\csc x$ Evaluate the sum of fractions on the left side of the equation: $\dfrac{\cos^{2}x}{\sin x}+\sin x=\csc x$ $\dfrac{\cos^{2}x+\sin^{2}x}{\sin x}=\csc x$ Since $\cos^{2}x+\sin^{2}x=1$, the identity is proved: $\dfrac{1}{\sin x}=\csc x$ $\csc x=\csc x$
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