Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Section 7.1 - Trigonometric Identities - 7.1 Exercises - Page 543: 24

Answer

$ \cot t $

Work Step by Step

Given expression is- $ \frac{\sin t}{1 - \cos t} - \csc t $ = $ \frac{\sin t}{1 - \cos t} - \frac{1}{\sin t} $ = $\frac{ \sin^{2} t - (1 - \cos t)}{(1 - \cos t) \sin t} $ = $\frac{ (1 -\cos^{2} t) - (1 - \cos t)}{(1 - \cos t) \sin t} $ (using first Pythagorean identity) = $\frac{ (1 -\cos t) (1 +\cos t) - (1 - \cos t)}{(1 - \cos t) \sin t} $ = $\frac{ (1 -\cos t) (1 +\cos t - 1 )}{(1 - \cos t) \sin t} $ = $\frac{ (1 -\cos t) \cos t }{(1 - \cos t) \sin t} $ = $\frac{ \cos t }{\sin t} $ = $ \cot t $
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