Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Section 7.1 - Trigonometric Identities - 7.1 Exercises - Page 543: 18

Answer

$\sin^{2} α$

Work Step by Step

Given expression is- $\sin^{4} α - \cos^{4} α + \cos^{2} α $ = $\sin^{4} α + \cos^{2} α - \cos^{4} α $ = $\sin^{4} α + \cos^{2} α ( 1 - \cos^{2} α) $ = $\sin^{4} α + \cos^{2} α \sin^{2} α$ ( From first Pythagorean identity, $1 - \cos^{2}α$ = $\sin^{2}α$) = $\sin^{2} α (\sin^{2} α + \cos^{2} α)$ ( From first Pythagorean identity, $ \sin^{2}α + \cos^{2}α$ = $1$) = $\sin^{2} α$
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